How to read images from 2 or more folders.

[JC243]

How to read images from 2 or more folders:

I have the folders:
img/p/a with 1000 files
img/p/b in 1000 files
img/p/c with 900 files

links.php the file I am modifying the line:

public function getImageLink($name, $ids, $type = null)
   {
return ($this->allow == 1) ? (__PS_BASE_URI__.$ids.($type ? '-'.$type : '').'/'.$name.'.jpg') : (_THEME_PROD_DIR_A_.$ids.($type ? '-'.$type : '').'.jpg');
   } 

change:

public function getImageLink($name, $ids, $type = null)
   {
return ($this->allow == 1) ? (__PS_BASE_URI__.$ids.($type ? '-'.$type : '').'/'.$name.'.jpg') : (_THEME_PROD_DIR_A_.$ids.($type ? '-'.$type : '').'.jpg');
return ($this->allow == 1) ? (__PS_BASE_URI__.$ids.($type ? '-'.$type : '').'/'.$name.'.jpg') : (_THEME_PROD_DIR_B_.$ids.($type ? '-'.$type : '').'.jpg');
return ($this->allow == 1) ? (__PS_BASE_URI__.$ids.($type ? '-'.$type : '').'/'.$name.'.jpg') : (_THEME_PROD_DIR_C_.$ids.($type ? '-'.$type : '').'.jpg');
   } 

It does not work, I only read the images of the first directory. Missing is any OR or AND, but not how, agradeze your help and there are many waiting for this change because my server does not support more than 1000 files per folder.

[web.geek]

I would bet it's the "return" keyword. That usually signals exiting the function at that point, so it may never even check the other folders. Try evaluating the conditions and storing the result in a local variable then only return the local variable. Maybe something like:

public function getImageLink($name, $ids, $type = null) {
   $link = ($this->allow == 1) ? (__PS_BASE_URI__.$ids.($type ? '-'.$type : '').'/'.$name.'.jpg') : (_THEME_PROD_DIR_A_.$ids.($type ? '-'.$type : '').'.jpg');
   $link = ($this->allow == 1) ? (__PS_BASE_URI__.$ids.($type ? '-'.$type : '').'/'.$name.'.jpg') : (_THEME_PROD_DIR_B_.$ids.($type ? '-'.$type : '').'.jpg');
   $link = ($this->allow == 1) ? (__PS_BASE_URI__.$ids.($type ? '-'.$type : '').'/'.$name.'.jpg') : (_THEME_PROD_DIR_C_.$ids.($type ? '-'.$type : '').'.jpg');

   return $link;
} 

This may not work exactly as written, because I don't have any place to test it right now; but it should give you a general idea of the concept. I'm not sure what $this->allow represents.

[JC243]

Like the previous code, only reads data located in the last directory "c ".

Do not like the expression.
Search in the "A", else, look in the "B", else, look in the "C" and so on.

Thanks.

[rojascristian]

Hello,
I have the same problem, my site has more than 14.000 images and my server doesn't allow more than 1000 files per folder. Do you have the anwser to my problem? Thanks