Failed to install a module in PHP 5.2.17

[jbastarras]

Hello,
 
I'm having problems with PHP 5.2.17 version installing a module. I get errors ( sintax error '[' ) with these lines

 

$context = stream_context_create($cparams);
  $fp = fopen($url, 'rb', false, $context);
 
  if (!$fp) {
$result = false;
} else {


   $result = stream_get_contents($fp);    
}


if(!$result) {
$result = ['codigo' => 'ERROR', 'descripcion' => 'Error de conexion ', 'tipo' => 'KO];
} else {
switch ($format) {
case 'json':
    $result = json_decode($result, true);
      if ($result === null) {
      $result = ['codigo' => 'ERROR', 'descripcion' => 'Error de conexion, 'tipo' => 'KO'];
      }
      break;
   case 'xml':
      $result = simplexml_load_string($result, true);
      if ($result === null) {
      $result = ['codigo' => 'ERROR', 'descripcion' => 'Error de conexion', 'tipo' => 'KO'];
      }
      break;
}
}

or 

public static function app($key) {
return self::config('app')[$key];
}

Is there any way to do this otherwise to be compatible with both versions ?
 
With 5.3 no problem
 
 
Thank You
 
Regards

 

[fred-vinapresta]

Hi, the best way would be to upgrade your php version, can't the hoster do that?

 

Anyway, try with that , replace your array 

['key1' => value1, 'key2' => value2]

by

array('key1'=>value1,'key2'=>value2);

[jbastarras]

Thanks 

 

I can´t change the version of php .

 

I solved  first block of code but  the second problem  I don´t know solve

public static function app($key) {
return self::config('app')[$key];
}

Thank you 

 

Regards

[bellini13]

Then you should find a new host.  PHP 5.2 is no longer supported and no longer receives updates. 

http://php.net/eol.php

 

If your host will not upgrade, then find a new host.  I realize that is not the answer to your question, but you are focused on the wrong thing.

 

Anyway, what does the function 'config' do?  And what does it return? 

return self::config('app')[$key];

[jbastarras]

Thanks but  change php version not depend on me 

 

app.php 

 

?php


return array(
'module_name' => 'module',
'cliente_api' => 'prestashop',
'url' => 'http://localhost:8080/url/ecommerce',
);

I want return a array in the app.php file

 

Thanks 

 

Regards

Edited February 19, 2015 by jbastarras (see edit history)

[bellini13]

It is not clear what you are trying to do.  the code you have provided is not even a function

[jbastarras]

I am calling an array of app.php file .

 

this is app.php 

?php


return array(
'module_name' => 'module',
'cliente_api' => 'prestashop',
'url' => 'http://localhost:8080/url/ecommerce',
);

And now I want to call the module property . I want return 'module' ( name of may module ) 

 

 

This is a util function that I use all of module of prestashop 

public static function app($key) {
return self::config('app')[$key];
}

But this sentence return self::config('app')[$key]; fail in Php version 5.2.7 

 

 

Thanks 

 

Regards

[bellini13]

And where is config defined?

return self::config('app')[$key];

[jbastarras]

Inside module 

 

module\config\app.php

[bellini13]

and what does it do?  and why not pass in the key to the config function?

 

instead of doing this

return self::config('app')[$key];

why not do this

return self::config('app', $key);

[jbastarras]

Not working ( return nothing )  and It fails also with version 5.3 . With 5.4 works

 

 

 Parse error: syntax error, unexpected '[' in C:\develop\prestashop\modules\module\classes\Util.php on line 10

[PrestaShop] Fatal error in module Util:
syntax error, unexpected '['

 

 

Thanks 

 

Regards

[bellini13]

why not answer my question?

 

instead of doing this

return self::config('app')[$key];

why not do this

return self::config('app', $key);

[jbastarras]

return self::config('app', $key); not working .

 

The function return a empty value 

 

 

Thanks

 

Regards

[bellini13]

and what does your config function do?

 

if you want help, you need to post all of your code.  this back and worth is just getting annoying.